What are the odds?
So just got thinking of this hand after reading about the guy at the WSOP who folded quads face up.
My worst bad beat ever was when my Straight Flush lost to the higher straight flush both hole cards used.. sadly it was in a freeroll and not in a 1/2 game to win the 500k bad beat that the casinos will have out here.
Just got me thinking how improbable is that?
For the record it was my 45 of spades vs his 910 of spades (duh)
My worst bad beat ever was when my Straight Flush lost to the higher straight flush both hole cards used.. sadly it was in a freeroll and not in a 1/2 game to win the 500k bad beat that the casinos will have out here.
Just got me thinking how improbable is that?
For the record it was my 45 of spades vs his 910 of spades (duh)
Comments
Oh wait, there is, and maybe if we all say his name 3 times he will answer our pleas.
Let's see... Blondefish! Blondefish! Blondefish!
That table was about 4 tables away from me. There was a french guy (with a european mullet) sitting directly to the left of the guy that folded the quads and we played together part of day 2. He came over after and said that the dealer was pitching the cards a little high they could see some of the cards coming out......they did ask the dealer to lower his hands while dealing but i guess it didn't work. The speculation was that the guy that folded may have seen one or both of the queen ten of spades. he did say an hour later that he had the straight flush.
that makes more sense....the guy that folded won a 3k PLO bracelet this year.....so not terrible.....I mean, as terrible as you'd have to be to fold quads
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There are 33,120 possible boards out of 2,598,960 that have three suited cards in a row, but none of the same suit 2 cards in either direction. (1.27%)
When one of the above flops happens there is a 0.8295% chance that one of the 9 players will have the two higher suited cards for the straight flush: 1 - [(1 - 2 / 47 * 1/46) ^ 9]
When one of the 9 hands has the top end of the straight flush there is a 0.80523% chance that one of the remaining 8 players will have the two lower cards for the straight flush: 1 - [(1 - 2/45 * 1/44) ^ 8]
Putting it all together, the chance of this worst case scenario is a 0.012744 * 0.008295 * 0.0080523 = 0.000000851179
= ~ 1 chance in 1,174,841 hands
But, looking at it another way - if you have the two low cards for a straight flush, there is a 0.80523% chance that one of the other 8 players at the table will have the top 2 cards for the straight flush (1 chance in 124)
Does that "So you're saying there's a chance" phrase works here? lol...