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math halp

UnknownUnknown
in Off Topic Lounge
Given x = 1 and y = 1, then:
x = y
Multiplying each side by x,
we get
x2 = xy
Subtracting y2 from each side, we get:
x2 - y2 = xy - y2
Factoring each side,
we get:
(x + y) (x - y) = y (x - y)
Dividing by the common term
(x - y), we get:
x + y = y
Substituting the given values,
we get:
1 + 1 = 1
Therefore:
2 = 1.



WAT


where the hell is the mistake???

Comments

  • Hellmuth's MoleHellmuth's Mole
    Nice clip and paste.


    Been done.



    Edit: Can't find the thread...have at it.
  • Richard~Richard~
    you just divided by zero

    to elaborate a bit your premise is that x = y then you perform an operation that is invalid if x = y
  • UnknownUnknown
    Hellmuth's Mole wrote: »
    Nice clip and paste.


    Been done.



    Edit: Can't find the thread...have at it.

    this is for an aptitude test for a job, not clipping and pasting anything.. but thanx for that input. its really appreciated and relevant!
  • Hellmuth's MoleHellmuth's Mole
    costanza wrote: »
    this is for an aptitude test for a job, not clipping and pasting anything.. but thanx for that input. its really appreciated and relevant!


    So the forum is applying for a job? What's it going to do? What's the pay like?
  • trigstrigs
    math halp

    it's spelled 'help'.

    you're welcome.
  • UnknownUnknown
    Hellmuth's Mole wrote: »
    So the forum is applying for a job? What's it going to do? What's the pay like?

    the forum isn't applying for anything, im just looking for help for something im obviously missing.

    troll somewhere else.
  • UnknownUnknown
    trigs wrote: »
    math halp

    it's spelled 'help'.

    you're welcome.

    "halp" is an internet meme way of asking for help.

    no thank you to your welcome offer.
  • UnknownUnknown
    costanza wrote: »
    the forum isn't applying for anything, im just looking for help for something im obviously missing.

    troll somewhere else.
    If this is really an aptitude test that you were sent home with to complete, then its likely they expect you to use the Internet and to find out that this question is not a correct question, from there they want to see how you would deal with the circumstance.

    Edit: which is possible to tilt you into angerful ragalistic sarcasmic state of unreason. Its possible they want to see if they confuse you will you get mad and press the nuclear meltdown button.
  • trigstrigs
    costanza wrote: »
    "halp" is an internet meme way of asking for help.

    no thank you to your welcome offer.

    pretty sure rich already gave you the answer.

    if x=1 and y=1 then (x-y)=0 and you can't divide by 0
  • Hellmuth's MoleHellmuth's Mole
    costanza wrote: »

    troll somewhere else.


    Nah, I like it under this bridge



    EDIT: Congrats on trying to get a job.
  • Hellmuth's MoleHellmuth's Mole
    Not a clip and paste but here's the original version.

    http://www.pokerforum.ca/f12/algebra-trick-25436/
  • UnknownUnknown
    trigs wrote: »
    pretty sure rich already gave you the answer.

    if x=1 and y=1 then (x-y)=0 and you can't divide by 0

    sigh.

    im a retard.

    tyty.
  • Richard~Richard~
    trigs wrote: »
    pretty sure rich already gave you the answer.

    if x=1 and y=1 then (x-y)=0 and you can't divide by 0

    the trick is you defined x to equal y in the premise. Thus x-y will always equal zero
  • UnknownUnknown
    Richard~ wrote: »
    the trick is you defined x to equal y in the premise. Thus x-y will always equal zero
    Does that make the answer 'x cannot equal y'?
  • UnknownUnknown
    darbday wrote: »
    Does that make the answer 'x cannot equal y'?

    no x can equal y , the value is the same, whether its 1 or 0
  • Richard~Richard~
    darbday wrote: »
    Does that make the answer 'x cannot equal y'?

    yes, you can do the same for x =/= y implies that x+y =/= y unless x=0 and y=/=x
  • Wetts1012Wetts1012
    darbday wrote: »
    Does that make the answer 'x cannot equal y'?

    Depends on how you look at it.

    I prefer to say that 'y cannot equal x'
  • MiloMilo
    Wetts1012 wrote: »
    Depends on how you look at it.

    I prefer to say that 'y cannot equal x'

    Letterism itt . . .
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