DataMn;401203 wroteAssuming 9 players see all 5 cards, and looking for the worst case scenario (straight flush over straight flush, each using 2 cards)
There are 33,120 possible boards out of 2,598,960 that have three suited cards in a row, but none of the same suit 2 cards in either direction. (1.27%)
When one of the above flops happens there is a 0.8295% chance that one of the 9 players will have the two higher suited cards for the straight flush: 1 - [(1 - 2 / 47 * 1/46) ^ 9]
When one of the 9 hands has the top end of the straight flush there is a 0.80523% chance that one of the remaining 8 players will have the two lower cards for the straight flush: 1 - [(1 - 2/45 * 1/44) ^ 8]
Putting it all together, the chance of this worst case scenario is a 0.012744 * 0.008295 * 0.0080523 = 0.000000851179
<b>= ~ 1 chance in 1,174,841 hands</b>
But, looking at it another way - if you have the two low cards for a straight flush, there is a 0.80523% chance that one of the other 8 players at the table will have the top 2 cards for the straight flush (1 chance in 124)
Does that "So you're saying there's a chance" phrase works here? lol...