The Prophet 22 If I am playing 8 games on one ticket and I want to play A - D on every ticket. How many tickets will I need to play to cover every combination on tickets with the other 4 games for vistors and home. Therefore if A-D win, I should have one winning ticket no matter what happens with E - H. Correct? Games A B C D E F G H Eample for 5 games One ticket A B C D E vistor Second ticket A B C D E home As long as A - D win, E game wont matter as I have one ticket for the vistor and one ticket for the home. My question is how do I do this for 8 games. You actually have to fill out every ticket. Prophet22
moose If zero is home and one is away then 1111 converted from binary to decimal is 15, add 0000 and you get 16 different combinations. 0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010 1011 1100 1101 1110 1111 Each column corresponds to game EFGH with 0 home and 1 away. Or 4 games with 2 outcomes is 4^2 = 16
MickeyHoldem woog30;394595 wroteI suggest not betting crazy parlays, you will not be profitable long term. Are you kidding.... I'm in the process of filling out 85,900,584 lotto max tickets... easy money!!!
The Prophet 22 woog30;394595 wroteI suggest not betting crazy parlays, you will not be profitable long term. I understand the parlay betting "scam". Not many here on the forum like NFL spreads for betting purposes only fantesy stats. This is an exercise with a few friends. My above question will only result in 7 team parlays and one team of 8. Thanks for your help