math halp

[deleted]

Given x = 1 and y = 1, then:
x = y
Multiplying each side by x,
we get
x2 = xy
Subtracting y2 from each side, we get:
x2 - y2 = xy - y2
Factoring each side,
we get:
(x + y) (x - y) = y (x - y)
Dividing by the common term
(x - y), we get:
x + y = y
Substituting the given values,
we get:
1 + 1 = 1
Therefore:
2 = 1.

WAT

where the hell is the mistake???

Hellmuth's Mole

Nice clip and paste.

Been done.

Edit: Can't find the thread...have at it.

Richard~

you just divided by zero

to elaborate a bit your premise is that x = y then you perform an operation that is invalid if x = y

[deleted]

Hellmuth's Mole;326031 wroteNice clip and paste.

Been done.

Edit: Can't find the thread...have at it.

this is for an aptitude test for a job, not clipping and pasting anything.. but thanx for that input. its really appreciated and relevant!

Hellmuth's Mole

costanza;326036 wrotethis is for an aptitude test for a job, not clipping and pasting anything.. but thanx for that input. its really appreciated and relevant!

So the forum is applying for a job? What's it going to do? What's the pay like?

trigs

math halp

it's spelled 'help'.

you're welcome.

[deleted]

Hellmuth's Mole;326037 wroteSo the forum is applying for a job? What's it going to do? What's the pay like?

the forum isn't applying for anything, im just looking for help for something im obviously missing.

troll somewhere else.

[deleted]

trigs;326038 wrotemath halp

it's spelled 'help'.

you're welcome.

"halp" is an internet meme way of asking for help.

no thank you to your welcome offer.

[deleted]

costanza;326040 wrotethe forum isn't applying for anything, im just looking for help for something im obviously missing.

troll somewhere else.

If this is really an aptitude test that you were sent home with to complete, then its likely they expect you to use the Internet and to find out that this question is not a correct question, from there they want to see how you would deal with the circumstance.

Edit: which is possible to tilt you into angerful ragalistic sarcasmic state of unreason. Its possible they want to see if they confuse you will you get mad and press the nuclear meltdown button.

trigs

costanza;326041 wrote"halp" is an internet meme way of asking for help.

no thank you to your welcome offer.

pretty sure rich already gave you the answer.

if x=1 and y=1 then (x-y)=0 and you can't divide by 0

Hellmuth's Mole

costanza;326040 wrote
troll somewhere else.

Nah, I like it under this bridge

EDIT: Congrats on trying to get a job.

Hellmuth's Mole

Not a clip and paste but here's the original version.

http://www.pokerforum.ca/f12/algebra-trick-25436/

[deleted]

trigs;326043 wrotepretty sure rich already gave you the answer.

if x=1 and y=1 then (x-y)=0 and you can't divide by 0

sigh.

im a retard.

tyty.

Richard~

trigs;326043 wrotepretty sure rich already gave you the answer.

if x=1 and y=1 then (x-y)=0 and you can't divide by 0

the trick is you defined x to equal y in the premise. Thus x-y will always equal zero

[deleted]

Richard~;326058 wrotethe trick is you defined x to equal y in the premise. Thus x-y will always equal zero

Does that make the answer 'x cannot equal y'?

[deleted]

darbday;326060 wroteDoes that make the answer 'x cannot equal y'?

no x can equal y , the value is the same, whether its 1 or 0

Richard~

darbday;326060 wroteDoes that make the answer 'x cannot equal y'?

yes, you can do the same for x =/= y implies that x+y =/= y unless x=0 and y=/=x

Wetts1012

darbday;326060 wroteDoes that make the answer 'x cannot equal y'?

Depends on how you look at it.

I prefer to say that 'y cannot equal x'

Milo

Wetts1012;326099 wroteDepends on how you look at it.

I prefer to say that 'y cannot equal x'

Letterism itt . . .